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Updated on : 2022-09-05

Solution

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Correct option is C)

Using $M=OI =uv .y_{c}=45−36 ×15=−12.$ Thus co-ordinates of $C_{_{′}}$ are (36.-12)

Thus coordinates of $B_{_{′}}$ are (33,-6.1)

Thus coordinates of $A_{_{′}}$ are (40.7,-21.4)

Length of image $A_{_{′}}B_{_{′}}=(40.7−33)_{2}+(21.4−6.1)_{2} =7.7_{2}+15.3_{2} =17.1cm$.

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