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Question

A 2 kW heater, a 200 W TV and three 100 W lamps are all switched on from 6 p.m. to 10 p.m. What is the total cost at Rs. 5.50 per kWh ?

Solution
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We know that,
Total energy conserved, E=p×t
=[2+0.2+3×0.1]×4hr
=2.5×4Rwh
=10Rwh
Rs5.50=10×5.50=Rs55
We get, Rs55.

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