For lamp I=5200.25A;R=200.25=80Ω
Current through the lamp should be 0.25A
(a) when condenser C is placed in series
i=200√R2+(1ωC)2=0.25
putting the value of ω=2π×50
∴C=4.0μF
(b) when inductor is used
I=200√R2+(ωL)2=0.25⇒L=2.53H
(c) when resistance is used
I=200R+r=0.25⇒r=720Ω