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Correct option is

It is because the lamp is operated at its rated voltage $V=220V$. So the power consumed will be equal to its power rating, i.e. $100W.$

Let us solve it to prove it.

We know, power $P=RV_{2} $

Putting $P=100W$ and $V=220V$

$⇒R=100(220)_{2} =484Ω$

By Ohm's law,

Current in the circuit $I=resistance Rpower supply voltage V $

$⇒I=484220 A$

Power consumed, P can be calculated as $I_{2}R.$

$P=(484220 )_{2}×484=484(220)_{2} =100W$

Hence, option (A) is correct.

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