A 2-digit number has tens digit greater than the unit is digit if the sum of its digits is equal to twice the difference, no. of such numbers possible are
Let 10x+y be the two digits number with digits x and y
according to question,
x>y.....(i)
and,
=x+y=2(x−y)
⇒x=32y
If y=1 then x=32
Not possible
∵digit must be positive integer
If y=2 then x=3
i.e 32
If y=3 then x=92
Not possible
∵digit must be positive integer
If y=4 then x=6
i.e 64
similarly
If y=6 then x=9 i.e 96
Hence there are three number which follows above condition (32),(64), and (96)