A 3-0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis- The magnetic field inside the solenoid is given to be 0-27 T- What is the magnetic force on the wire-

Question

Toppr Admin · Accepted Answer

-x3B8-90oFor magnetic forceF-BIlsin-x3B8-8-1-xD7-10-x2212-2NDirection of force can be obtained from Fleming-apos-s left hand rule-

Column $I$	Column $I I$
$a .$ Magnetic field inside a long straight solenoid is	$p .$ not constant
$b .$ Magnetic field inside a toroidal solenoid is	$q .$ zero
$c .$ Magnetic field inside a conducting hollow pipe having current parallel to its axis is	$r .$ constant
$d .$ Magnetic field due to current carrying wire on its surface is	$s .$ maximum

A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?

$θ = 90^{o}$
For magnetic force
$F = B I l s i n θ = 8.1 \times 10^{- 2} N$
Direction of force can be obtained from Fleming's left hand rule.

A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?

θ=90oFor magnetic forceF=BIlsinθ=8.1×10−2NDirection of force can be obtained from Fleming's left hand rule.

$θ = 90^{o}$
For magnetic force
$F = B I l s i n θ = 8.1 \times 10^{- 2} N$
Direction of force can be obtained from Fleming's left hand rule.