A 3-0 N force applied on a 0-40 kg mass makes the mass move a constant speed of 3-0 -m-s-1- held back by friction- In the span of it moving through 4-0 m- the net work done on the mass is-0 J12 J0-90 J-12 J-0-90 J

Question

Toppr Admin · Accepted Answer

As the mass is moving with a constant speed, thus net external force acting on the mass is zero.
$F_{n e t} = 0$
Displacement of the mass
$S = 4.0$ m
Net work done on the mass
$W_{n e t} = F_{n e t} \times S$
$\Rightarrow W_{n e t} = 0 J$

A 3.0 N force applied on a 0.40 kg mass makes the mass move at a constant speed of 3.0 ms−1, held back by friction. In the span of it moving through 4.0 m, the net work done on the mass is:0 J12 J0.90 J−12 J−0.90 J

As the mass is moving with a constant speed, thus net external force acting on the mass is zero.Fnet=0Displacement of the mass S=4.0 mNet work done on the mass Wnet=Fnet×S⇒Wnet=0 J

A $3.0 N$ force applied on a $0.40 k g$ mass makes the mass move at a constant speed of $3.0 m s^{- 1}$ , held back by friction. In the span of it moving through $4.0 m$ , the net work done on the mass is:
$0 J$
$12 J$
$0.90 J$
$- 12 J$
$- 0.90 J$

As the mass is moving with a constant speed, thus net external force acting on the mass is zero.
$F_{n e t} = 0$
Displacement of the mass
$S = 4.0$ m
Net work done on the mass
$W_{n e t} = F_{n e t} \times S$
$\Rightarrow W_{n e t} = 0 J$