a 37 NR and A$1 = 32, then the value of a 13. I A=1 12 2a is (1) #1 (3) +3 (2) +2 (4) 14

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Find the value of:
(i) (2⁰ + 3⁻¹) × 3²
(ii) (2⁻¹ × 3⁻¹) ÷ 2⁻³
(iii)

{(\frac{1}{2})}^{- 2} + {(\frac{1}{3})}^{- 2} + {(\frac{1}{4})}^{- 2}

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Simplify:
(i)

\"{\"{(\frac{1}{3})}^{- 3} - {(\frac{1}{2})}^{- 3}\"}\" \div {(\frac{1}{4})}^{- 3}

(ii)

(3^{2} - 2^{2}) \times {(\frac{2}{3})}^{- 3}

(iii)

{\"{\"{(\frac{1}{2})}^{- 1} \times (- 4)^{- 1}\"}\"}^{- 1}

(iv)

{\"[\"{\"{\"{(\frac{- 1}{4})}^{2}\"}\"}^{- 2}\"]\"}^{- 1}

(v)

{\"{\"{(\frac{2}{3})}^{2}\"}\"}^{3} \times {(\frac{1}{3})}^{- 4} \times 3^{- 1} \times 6^{- 1}

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Question) Simplify :

(i) \{{(\frac{1}{3})}^{- 3} - {(\frac{1}{2})}^{- 3}\} \div {(\frac{1}{4})}^{- 3}

i i) (3^{2} - 2^{2}) \times {(\frac{2}{3})}^{- 3} (i i i) {\{{(\frac{1}{2})}^{- 1} \times {(- 4)}^{- 1}\}}^{- 1} (i v) {[{\{{(\frac{- 1}{4})}^{2}\}}^{- 2}]}^{- 1}

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Let A = { 10, 11, 12, 13, 14 }; B = { 0, 1, 2, 3, 5 } and

f i : A \to B, i = 1, 2, 3

. State the type of function for the following (give reason):
(i)

f_{1}

= { (10, 1), (11, 2), (12, 3), (13, 5), (14, 3) }
(ii)

f_{2}

= { (10, 1), (11, 1), (12, 1), (13, 1), (14, 1) }
(iii)

f_{3}

= { (10, 0), (11, 1), (12, 2), (13, 3), (14, 5) }

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Simplify:
(i)

\{{(\frac{1}{3})}^{- 3} - {(\frac{1}{2})}^{- 3}\} \div {(\frac{1}{4})}^{- 3}

(ii)

(3^{2} - 2^{2}) \times {(\frac{2}{3})}^{- 3}

(iii)

{\{{(\frac{1}{2})}^{- 1} \times (- 4)^{- 1}\}}^{- 1}

(iv)

{[{\{{(\frac{- 1}{4})}^{2}\}}^{- 2}]}^{- 1}

(v)

{\{{(\frac{2}{3})}^{2}\}}^{3} \times {(\frac{1}{3})}^{- 4} \times 3^{- 1} \times 6^{- 1}

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