Question

A $$40 \mu F$$ capacitor is connected to a $$200 V,\ 50 Hz \ ac$$ supply. The rms value of the current
in the circuit is, nearly :

Answer 1

Correct option is B. $$2.5 A$$
RMS value of applied voltage = $$200\ V$$
Impedance of a capacitor is given by:
$$X_c=\dfrac{1}{2\pi f C}$$
Hence, rms current through it is:
$$I_{rms}=\dfrac{V}{X_C}$$

$$I_{rms}=200 \times 2 \times \pi \times 50 \times 40 \times 10^{-6}$$

$$I_{rms}=2.51 \ A$$