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Question

A 4.00μF capacitor and a 6.00μF capacitor are connected in parallel across a 660Vsupply line. Find the charge on each capacitor and the voltage across each of them.

Solution
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As the both capacitor are in parallel so potential across them will be same i.e 660V.

Now using Q=CV, the charge on 4μF is Q1=(4×106)×660=2.64×103C and the charge on 6μF is Q2=(6×106)×660=3.96×103C

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