A 4.0-cm-high object is placed at a distance of 60 cm from a concave lens of focal length 20 cm. Find the size of the image.
2.5cm
1.0cm
3.0cm
4.0cm
A
1.0cm
B
2.5cm
C
3.0cm
D
4.0cm
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Solution
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We have f=−20cm and u=−60cm
For a lens,
1v−1u=1f
or, 1v=1u+1f=1−60+1−20=−115
The magnification is: m=heho=vu=−15−60=14
or, he=ho4=4.04=1.0cm
So the image is 1.0cm high. The positive sign shown that is erect.
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