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Question

A 44 mH inductor is connected to 220 V, 50 Hz ac supply. Determine the rms value of the current in the circuit.

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Solution

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We know that $X_{L} = ω L = 2 π f L = 2 \times 3.14 \times 50 \times 44 \times 10^{- 3} = 13.82 Ω$

Therefore, $I_{r m s} = \frac{E}{X_{L}} = \frac{220}{13.82} = 15.92 A$

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