A 50 litre vessel is equally divided into three parts with the help of two stationary semi permeable membrane(SPM). The vessel contains 60g $H_{2}$ gas in the left chamber, 160g $O_{2}$ in the middle and 140g $N_{2}$ in the right one. The left SPM allows transfer of only $H_{2}$ gas while the right one allows the transfer of both $H_{2}$ and $N_{2}$ . The final ratio of pressure in the three chambers:

Question

A 50 litre vessel is equally divided into three parts with the help of two stationary semi permeable membrane(SPM). The vessel contains 60g

H_{2}

gas in the left chamber, 160g

O_{2}

in the middle and 140g

N_{2}

in the right one. The left SPM allows transfer of only

H_{2}

gas while the right one allows the transfer of both

H_{2}

and

N_{2}

. The final ratio of pressure in the three chambers:

Toppr Admin · Accepted Answer

SPM will permit the flow of asses till -concentration became equal in each chambers- -of respective gas-At equilibrium- Moles of H2 in each member -302-10 moles-Moles- of N2 in right and middle chamber -52-2-5moles So- total number of moles in left chamber -10-total number of moles in middle chamber -2-x22C5-5-10-5-17-x22C5-5- total number of moles in right chamber -2-5-10-12-5-Now- here volume and temperature of each chamber remain constantSo- p-xA0-x3B1-xA0-n-xA0-Thus-xA0-PL-Pm-PR-nL-nm-nR-10-17-5-12-5-4-7-5So- option -A- is correct-