A 500 kg car takes a round turn of radius 50m with a speed of 36 km/hr. The centripetal force acting on the car will be

Question

A 500 kg car takes a round turn of radius 50 m with a velocity of 36 km-hr- The centripetal force is250 N1000 N750 N1200 N

Toppr Admin · Accepted Answer

Given - -xA0- -xA0- -xA0-m-500kg -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- R-50 mVelocity of the car -xA0- -xA0- -xA0- -xA0-v-36km-hr-36-xD7-518-10m-s -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-x2234- Centripetal force -xA0- -xA0- -xA0-F-mv2R-500-xD7-10250-1000N

A $500 k g$ car takes a round turn of radius $50 m$ with a velocity of $36 k m / h r$ . The centripetal force is
$250 N$
$1000 N$
$750 N$
$1200 N$

Given : $m = 500 k g$ $R = 50$ m
Velocity of the car $v = 36 k m / h r = 36 \times \frac{5}{18} = 10 m / s$

$∴$ Centripetal force $F = \frac{m v^{2}}{R} = \frac{500 \times 10^{2}}{50} = 1000 N$

A 500 kg car takes a round turn of radius 50 m with a velocity of 36 km/hr. The centripetal force is250N1000 N750N1200N

Given : m=500kg R=50 mVelocity of the car v=36km/hr=36×518=10m/s ∴ Centripetal force F=mv2R=500×10250=1000N

A $500 k g$ car takes a round turn of radius $50 m$ with a velocity of $36 k m / h r$ . The centripetal force is
$250 N$
$1000 N$
$750 N$
$1200 N$

Given : $m = 500 k g$ $R = 50$ m
Velocity of the car $v = 36 k m / h r = 36 \times \frac{5}{18} = 10 m / s$

$∴$ Centripetal force $F = \frac{m v^{2}}{R} = \frac{500 \times 10^{2}}{50} = 1000 N$