A $$ 50$$kg man with $$ 20$$kg load on his head climbs up $$ 20$$ steps of $$ 0.25 $$m height each. The work done in climbing is
Correct option is D. $$ 3430 J $$
Total mass = $$ (50 +20) = 70 kg $$
Total height = $$ 20 \times 0.25 = 5 m $$
Work done = increase in potential energy
$$W=PE\uparrow$$
$$ \therefore $$ work done = $$ mgh = 70 \times 9.8 \times 5 = 3430 J $$