A 60μF capacitor is connected to a 110 V, 60 Hz ac supply. Determine the rms value of the current in the circuit.
Given: The capacitance of the capacitor is 60μF.
The RMS value of the voltage supplied is 110V.
The frequency of the AC supply is 60Hz.
To find: The RMS value of the current.
We know that the impedance of the capacitor is determined by:
XC=1ωC=12πfC⇒12×3.14×60×60×10−6
⇒44.2Ω
The RMS value of the current is obtained as
Irms=EXC⇒11044.2⟹2.49 A