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Question

(a) A circular coil of 30 turns and radius 8.0 cm carrying a current of 6.0 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.0 T. The field lines make an angle of 60 with the normal of the coil. Calculate the magnitude of the counter torque that must be applied to prevent the coil from turning.
(b) Would your answer change, if the circular coil in (a) were replaced by a planar coil of some irregular shape that encloses the same area? (All other particulars are also unaltered.)

Solution
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(a)
n=30,r=0.08,A=πr2,θ=60o
Torque is given by, τ=nBIAsinθ=3.133 Nm

(b)
No, the answer is unchanged because the formula =NIAB is true for a planar loop of any shape.

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