-a- Find the acceleration of the car6 m-s-28 m-s-2- 2- m-s-24 m-s-2

Question

Toppr Admin · Accepted Answer

Given-Initial velocity u-5-xA0-m-sFinal velocity v-25-xA0-m-sTime t-10-xA0-sFrom the equation of motion v-u-at we get-acceleration a-v-x2212-ut-25-x2212-510-2-xA0-m-s2

(a) Find the acceleration of the car
$6 m / s^{2}$
$8 m / s^{2}$
$2 m / s^{2}$
$4 m / s^{2}$

Given:
Initial velocity $u = 5 m / s$
Final velocity $v = 25 m / s$
Time $t = 10 s$
From the equation of motion $v = u + a t$ we get,
acceleration $a = \frac{v - u}{t} = \frac{25 - 5}{10} = 2 m / s^{2}$

(a) Find the acceleration of the car6m/s28m/s22m/s24m/s2

Given:Initial velocity u=5 m/sFinal velocity v=25 m/sTime t=10 sFrom the equation of motion v=u+at we get,acceleration a=v−ut=25−510=2 m/s2

(a) Find the acceleration of the car
$6 m / s^{2}$
$8 m / s^{2}$
$2 m / s^{2}$
$4 m / s^{2}$

Given:
Initial velocity $u = 5 m / s$
Final velocity $v = 25 m / s$
Time $t = 10 s$
From the equation of motion $v = u + a t$ we get,
acceleration $a = \frac{v - u}{t} = \frac{25 - 5}{10} = 2 m / s^{2}$