A and B are two alloys of gold and copper prepared by mixing metals in the ratio of 5:3 and 5:11 respectively. Equal quantities of these alloys are melted to form a third alloy C. The ratio of gold and copper in alloy C is:
25:13
33:15
15:17
17:15
A
25:13
B
33:15
C
15:17
D
17:15
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Solution
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Total quantities of Alloy A=5+3=8
Total quantity of Alloy B=5+11=16
LCM of 8 and 16 is 16.
Then we have quantity of A in C as (10+6)
We have quantity of A and B as (5+11)
Hence the ratio is (10+5):(6+11)⟹15:17.
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