A and B are two alloys of gold and copper prepared by mixing metals in the ration 7:2 and 7:11 respectively. If equal quantities of the alloys are melted to form a third alloy C, the ratio of gold and copper in C will be
5:7
7:5
9:5
5:9
A
5:7
B
9:5
C
5:9
D
7:5
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Solution
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Since we mix equal quantities, we take LCM of 9 and 18 =18. Then we have 14+4 in the first and 7+11 in the second. ∴ Required ratio =(14+7):(4+11)=21:15=7:5.
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