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Question

A astronomical telescope has objective and eyepiece of focal lengths 40 cm and 4 cm respectively. To view an object 200 cm away from the objective, the lenses must be separated by a distance:
  1. 54.0 cm
  2. 37.3 cm
  3. 46.0 cm
  4. 50.0 cm

A
37.3 cm
B
46.0 cm
C
50.0 cm
D
54.0 cm
Solution
Verified by Toppr

On applying the lens formula for the objective lens:

1f0=1v01u0

1v0=1f0+1u0

1v0=140+1200

v0=50 cm

Therefore, tube length =v0+fe=50+4=54 cm

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