A bag contains 3 red balls- 4 blue balls- and 1 yellow ball- all the balls being identical in shape and size- If a ball is taken out of the bag without looking into it- the probability that the ball is not yellow-

Question

Toppr Admin · Accepted Answer

The total number of balls in the bag - 3 - 4 - 1 - 8- ballsSo- the number of possible outcomes - 8 - n-S-Probability of not drawing a yellow ball - 1 - Probability of drawing a yellow ballThus- probability of not drawing a yellow ball - 1 -8211-160-1-8 - -8 -8211- 1- 8 - 7-8-

A bag contains $$3$$ red balls, $$4$$ blue balls, and $$1$$ yellow ball, all the balls being identical in shape and size. If a ball is taken out of the bag without looking into it; find the probability that the ball is not yellow.

The total number of balls in the bag $$= 3 + 4 + 1 = 8$$ balls
So, the number of possible outcomes $$= 8 = n(S)$$
Probability of not drawing a yellow ball $$= 1 -$$ Probability of drawing a yellow ball
Thus, probability of not drawing a yellow ball $$= 1 – 1/8 = (8 – 1)/ 8 = 7/8$$

A bag contains $$3$$ red balls, $$4$$ blue balls, and $$1$$ yellow ball, all the balls being identical in shape and size. If a ball is taken out of the bag without looking into it; find the probability that the ball is not yellow.

The total number of balls in the bag $$= 3 + 4 + 1 = 8$$ ballsSo, the number of possible outcomes $$= 8 = n(S)$$Probability of not drawing a yellow ball $$= 1 -$$ Probability of drawing a yellow ballThus, probability of not drawing a yellow ball $$= 1 – 1/8 = (8 – 1)/ 8 = 7/8$$

The total number of balls in the bag $$= 3 + 4 + 1 = 8$$ balls
So, the number of possible outcomes $$= 8 = n(S)$$
Probability of not drawing a yellow ball $$= 1 -$$ Probability of drawing a yellow ball
Thus, probability of not drawing a yellow ball $$= 1 – 1/8 = (8 – 1)/ 8 = 7/8$$