A bag contains 3 red balls- 4 blue balls and 1 yellow ball- all the balls being identical in shape and size- If a ball is taken out of the bag without looking into it- the probability that the ball is red-

Question

Toppr Admin · Accepted Answer

The total number of balls in the bag - 3 - 4 - 1 - 8- ballsSo- the number of possible outcomes - 8 - n-S-Event of drawing a red ball - -R- R- R-So- -n-E- - 3-Thus- probability of drawing a red ball -160-n-E- n-S- - 3-8-

A bag contains $$3$$ red balls, $$4$$ blue balls and $$1$$ yellow ball, all the balls being identical in shape and size. If a ball is taken out of the bag without looking into it; find the probability that the ball is red.

The total number of balls in the bag $$= 3 + 4 + 1 = 8$$ balls
So, the number of possible outcomes $$= 8 = n(S)$$
Event of drawing a red ball $$= {R, R, R}$$
So, $$n(E) = 3$$
Thus, probability of drawing a red ball $$= n(E)/ n(S) = 3/8$$

A bag contains $$3$$ red balls, $$4$$ blue balls and $$1$$ yellow ball, all the balls being identical in shape and size. If a ball is taken out of the bag without looking into it; find the probability that the ball is red.

The total number of balls in the bag $$= 3 + 4 + 1 = 8$$ ballsSo, the number of possible outcomes $$= 8 = n(S)$$Event of drawing a red ball $$= {R, R, R}$$So, $$n(E) = 3$$Thus, probability of drawing a red ball $$= n(E)/ n(S) = 3/8$$

The total number of balls in the bag $$= 3 + 4 + 1 = 8$$ balls
So, the number of possible outcomes $$= 8 = n(S)$$
Event of drawing a red ball $$= {R, R, R}$$
So, $$n(E) = 3$$
Thus, probability of drawing a red ball $$= n(E)/ n(S) = 3/8$$