A bag contains $3$ white, $5$ black, and $2$ red balls, all of the same shape and size. A ball is drawn from the bag without looking into it, find the probability that the ball is drawn is not a red ball.

Question

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Answer 1

In a bag $3$ balls are white
$2$ balls are red
$5$ balls are black
Total number of balls $= 3 + 2 + 5 = 10$
Number of possible outcome $= 10$
Number of favourable outcome $= 3 + 5 = 8$
Not a red ball
$P (E) = \frac{N u m b e r o f f a v a o u r a b l e o u t c o m e}{N u m b e r o f a l l p o s s i b l e o u t c o m e} = \frac{8}{1 0} = \frac{4}{5}$

Answer 2

In a bag

3

balls are white

2

balls are red

5

balls are black
Total number of balls

= 3 + 2 + 5 = 10

Number of possible outcome

= 10

Number of favourable outcome

= 3 + 5 = 8

Not a red ball

P (E) = \frac{N u m b e r o f f a v a o u r a b l e o u t c o m e}{N u m b e r o f a l l p o s s i b l e o u t c o m e} = \frac{8}{1 0} = \frac{4}{5}