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$$2$$ balls are red

$$5$$ balls are black

Total number of balls $$=3+2+5=10$$

Number of possible outcome $$=10$$

Number of favourable outcome $$=3+5=8$$

Not a red ball

$$P(E)=\dfrac{Number\ of\ favaourable\ outcome}{Number\ of\ all\ possible\ outcome}=\dfrac{8}{10}=\dfrac{4}{5}$$

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