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Question

A bag contains $6$ black, $5$ white balls. One ball is drawn randomly. the probability of it being a white ball is.......

A

$\frac{6}{1 1}$

B

$\frac{5}{1 1}$

C

$\frac{1}{1 1}$

D

$\frac{2 7}{1 2 8}$

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Solution

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Correct option is B)

Total number of balls in the bag, $n (S) = 6 + 5 = 11$
Hence the probability of it being a white ball is $=$ $\frac{n ( E )}{n ( S )} = \frac{5}{1 1}$

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