Solve Study Textbooks Guides

Use app

Login

Question

A bag contains $6$ black, $5$ white balls. One ball is drawn randomly. The probability of it being a black ball is......

A

$\frac{6}{1 1}$

B

$\frac{5}{1 1}$

C

$\frac{1}{1 1}$

D

$\frac{2 7}{1 2 8}$

Easy

Open in App

Solution

Verified by Toppr

Correct option is A)

Total number of balls in the bag, $n (S) = 6 + 5 = 11$
Hence the probability of it being a black ball is $=$ $\frac{n ( E )}{n ( S )} = \frac{6}{1 1}$

Was this answer helpful?

0

0

Similar questions

A bag contains $6$ black, $5$ white balls. One ball is drawn randomly. the probability of it being a white ball is.......

A bag contains 8 black and 7 white balls. Two balls are drawn at random. Then for which the probability is more when

A bag contains $6$ black and $8$ white balls. One ball is drawn at random. What is the probability that the ball drawn is white?

A bag contains $9$ black and $12$ white balls. One ball is drawn at random. What is the probability that the drawn ball is white ?

A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?