A bag contains Rs 90 in coins- If coins of 50 paise- 25 paise and 10 paise are in the ratio 2-3-5- then the number of 25 paise coins in the bag are130135140120

Question

Toppr Admin · Accepted Answer

Let there be 2x- 3x and 5x coins of 50 p- 25 p- and 10 p-x21D2-50-xD7-2x-25-xD7-3x-10-xD7-5x-90-xD7-100-x21D2-225x-9000-x21D2-3x-9000225-xD7-3-120-

A bag contains Rs $90$ in coins. If coins of $50$ paise, $25$ paise and $10$ paise are in the ratio $2 : 3 : 5$ , then the number of $25$ paise coins in the bag are
$130$
$135$
$140$
$120$

Let there be 2x, 3x and 5x coins of 50 p, 25 p, and 10 p.
$\Rightarrow 50 \times 2 x + 25 \times 3 x + 10 \times 5 x = 90 \times 100$
$\Rightarrow 225 x = 9000$
$\Rightarrow 3 x = \frac{9000}{225} \times 3 = 120$ .

A bag contains Rs 90 in coins. If coins of 50 paise, 25 paise and 10 paise are in the ratio 2:3:5, then the number of 25 paise coins in the bag are130135140120

Let there be 2x, 3x and 5x coins of 50 p, 25 p, and 10 p.⇒50×2x+25×3x+10×5x=90×100⇒225x=9000⇒3x=9000225×3=120.

A bag contains Rs $90$ in coins. If coins of $50$ paise, $25$ paise and $10$ paise are in the ratio $2 : 3 : 5$ , then the number of $25$ paise coins in the bag are
$130$
$135$
$140$
$120$

Let there be 2x, 3x and 5x coins of 50 p, 25 p, and 10 p.
$\Rightarrow 50 \times 2 x + 25 \times 3 x + 10 \times 5 x = 90 \times 100$
$\Rightarrow 225 x = 9000$
$\Rightarrow 3 x = \frac{9000}{225} \times 3 = 120$ .