A ball is allowed to fall freely from a height of 3 metres on to a fixed plate. The successive rebound heights are h1,h2,h3,… lf the distance covered by the ball before coming to rest is y metres, find y. (Given that the coefficient of restitution is 0.5)
Let v1 be the velocity with which the ball strikes the plate v′1 be the velocity of rebound.
Let H be the height from which the ball is dropped.
v1=√2gH
v′1=√2gh1
⇒e=v1′v1=√h1H
e2=h1H⇒h1=e2H
Similarly,
h2=e2h1=e4H and so on.
Total distance described before it comes to stop
y=H+2h1+2h2+2h3+....
=H+2e2H+2e4H+2e6H+..
=H(1+2e2+2e4+2e6+....)
=H[1+2e2(1+e2+e4+...)]
=H[1+2e2.11−e2]
=H[1+e21−e2]
=3[1+0.521−0.52]=5metres