A ball is dropped from the top of a tower of height 80 m. At the same time, another ball is projected horizontally from the tower. Find the time taken by both the balls to reach the ground. (Take g = 10 ms−2).
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Vertical velocity of both balls is initially is zero. So, s=ut+21at2 80=s=0+21×10×t2 16=t2 t = 4 sec for both balls.