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Question

A ball is projected horizontally with a velocity of $$ 5ms^{-1} $$ from the top of a tower of height 10 m. When it reaches the ground ( $$ g = 10 ms^{-2} $$ )

A
The horizontal component of its velocity is $$ 14 ms^{_1} $$
B
Its velocity is $$ 15ms^{_1} $$
C
Its velocity is $$ \frac{29}ms{_1} $$
D
Vertical component of its velocity is $$ 15ms^{-1} $$
Solution
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Correct option is A. Vertical component of its velocity is $$ 15ms^{-1} $$
$$ V = \sqrt{2gh} = \sqrt{2 \times 10 \times 10}$$
$$ Vy = 10\sqrt{2} $$
$$ Vx = 5 m/s $$ same
$$ V = \sqrt{Vx^{2} + Vy^{2}} $$
$$ = \sqrt{200 + 25} $$
$$ = \sqrt{225} $$
$$ = 15 $$

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