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A ball is thrown vertically upwards with a given velocity such that it rises for T seconds (T > 1). What is the distance traversed by the ball during the last one second of ascent (in meters) ? (Acceleration due to gravity is g $m / s^{2}$ ) .
$v + g \frac{(1 - 2 T)}{2}$
$v T + \frac{1}{2} g [T^{2} - (T - 1)^{2}]$
$\frac{g}{2}$
$\frac{1}{2} g [T^{2} - (T - 1)^{2}]$

A

v + g \frac{(1 - 2 T)}{2}

B

\frac{g}{2}

C

\frac{1}{2} g [T^{2} - (T - 1)^{2}]

D

v T + \frac{1}{2} g [T^{2} - (T - 1)^{2}]

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