A ball of mass m moving with velocity v collides head-on with the second ball of mass m at rest. If the coefficient of restitution is e and velocity of first ball after collision is v1 and velocity of second ball after collision is v2 then
v1=(1−e)v2,v2=(1+e)v2
v1=v2,v2=−v2
v1=(1+e)v2,v2=(1−e)v2
v1=u,v2=−u
A
v1=(1−e)v2,v2=(1+e)v2
B
v1=v2,v2=−v2
C
v1=(1+e)v2,v2=(1−e)v2
D
v1=u,v2=−u
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Solution
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mv+0=mv1+mv2 ⇒v=v1+v2.....(1) and e=v2−v1u1−u2 e=v2−v1v−0....(2) and v2−v1=ev v2+v1=v 2v2=v(1+e)⇒v2=v(1+e)2 and v1=v(1−e)2
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