A bar magnet for dipole moment 104JT−1 is free to rotate around a horizontal plane. A horizontal magnetic field 4×10−5T exists on the space. Find the work done in rotating the magnet slowly from a direction parallel to the field to a direction 600 from the field.
0.1J
0.2J
0.4J
0.5J
A
0.4J
B
0.5J
C
0.1J
D
0.2J
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Solution
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W=MB(cos0−cos60) W=12MB W=12×4×10−5×104 W=0.2J
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