0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

# A bar magnet has a coercivity of 4×103Am−1. It is placed inside a solenoid of length 12 cm having 60 turns in order to demagnetize it, the amount of current that should be passed through the solenoid is:16 A8A 4 A2 A

A
2 A
B
8A
C
16 A
D
4 A
Solution
Verified by Toppr

#### Given: H=4×103 Am−1 L=12 cm N=60Bar magnet requires a magnetic intensity (H=4×103 Am−1) to become demagnetized.Let n be the number of turns per unit length.⇒n=NL=600.12=500 turns/metre Now, H=nI⇒I=Hn=4×103500=8 A

1
Similar Questions
Q1
A bar magnet has a coercivity of 4×103Am1. It is placed inside a solenoid of length 12 cm having 60 turns in order to demagnetize it, the amount of current that should be passed through the solenoid is:
View Solution
Q2
A bar magnet has coercivity 4×103Am1. It is desired to demagnetize it by inserting it inside a solenoid 12cm long and has 60turns. The current that should be sent through the solenoid is:
View Solution
Q3
A magnet has coercivity of 3×103 Am1. It is kept in a 10cm long solenoid with a total of 50 turns. How much current has to be passed through the solenoid to demagnetize it?
View Solution
Q4
A bar magnet has coercivity 4×103Am1. It is placed in a solenoid having 40 turns per cm and is 1.2m long. The current carried by the solenoid to demagnetize the bar magnet is :
View Solution
Q5
The coercivity of a small bar magnet is 4×103A/m. It is inserted inside a solenoid of 500 turns and length 1m to demagnetise it. The amount of current to be passed through the solenoid will be :
View Solution