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- 16 A
- 8A
- 4 A
- 2 A

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Solution

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Given: H=4×103 Am−1

L=12 cm

N=60

Bar magnet requires a magnetic intensity (H=4×103 Am−1) to become demagnetized.

Let n be the number of turns per unit length.

⇒n=NL=600.12=500 turns/metre

Now, H=nI

⇒I=Hn=4×103500=8 A

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