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Question

# A bar magnet has pole strength 1Am and is placed as shown in Fig. 24.19(a). Find the magnetic field at P.11μT19μT14μT22μT

A
14μT
B
19μT
C
22μT
D
11μT
Solution
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#### SN=6cm, SP=8cm, NP=√82+62=10cmMagnetic field due to south pole is BS=μ0M4πr2=μ0M4π(8×10−2)2Magnetic field due to north pole is BN=μ0M4πr2=μ0M4π(10×10−2)2B=√B2S+B2N+2BSBNcos143

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