Question

A bar magnet has pole strength $1Am$ and is placed as shown in Fig. $24.19$(a). Find the magnetic field at $P$.

Answer 1

$SN=6cm$, $SP=8cm$, $NP=\sqrt{8^2+6^2}=10cm$
Magnetic field due to south pole is $B_S=\frac{{\mu }_{0}M}{4\pi r^2}=\frac{{\mu }_{0}M}{4\pi (8\times {10}^{-2}{)}^2}$
Magnetic field due to north pole is $B_N=\frac{{\mu }_{0}M}{4\pi r^2}=\frac{{\mu }_{0}M}{4\pi (10\times {10}^{-2}{)}^2}$
$B=\sqrt{B_S^2+B_N^2+2B_S{B}_N\cos 143}$