A bar magnet has pole strength 1Am and is placed as shown in Fig. 24.19(a). Find the magnetic field at P.
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SN=6cm, SP=8cm, NP=√82+62=10cm Magnetic field due to south pole is BS=μ0M4πr2=μ0M4π(8×10−2)2 Magnetic field due to north pole is BN=μ0M4πr2=μ0M4π(10×10−2)2 B=√B2S+B2N+2BSBNcos143
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