A bar magnet is demagnetized by inserting it inside a solenoid of length 0.2 m, 100 turns, and carrying a curent of 5.2 A. The coercivity of the bar magnet is:
A
2600 A/m
B
520 A/m
C
285 A/m
D
1200 A/m
Hard
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Updated on : 2022-09-05
Solution
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Correct option is A)
Given:Length of solenoid l = 0.2 m
No. of turns N = 100
Current I = 5.2 A
To find : Coercivity of bar magnet H
Solution :
Coercivity of bar magnet H = nI
Now, n = lN
Therefore, H = lN×I = 0.2100×5.2 = 26×100 = 2600