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# A bar magnet is demagnetized by inserting it inside a solenoid of length 0.2 m, 100 turns, and carrying a curent of 5.2 A. The coercivity of the bar magnet is:2600 A/m520 A/m285 A/m1200 A/m

A
2600 A/m
B
285 A/m
C
520 A/m
D
1200 A/m
Solution
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#### Given:Length of solenoid l = 0.2 m No. of turns N = 100 Current I = 5.2 ATo find : Coercivity of bar magnet HSolution : Coercivity of bar magnet H = nI Now, n = NlTherefore, H = Nl×I = 1000.2×5.2 = 26×100 = 2600H = 2600 A/mHence A is the correct option

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