Question

This question has multiple correct options

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Updated on : 2022-09-05

Solution

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Correct options are A) and C)

$L_{i}=MVL/2$

$L_{f}=Iω$

Since both rods stick together it becomes a rod of mass $2M$ and length $2L$

Hence, $L_{f}=Iω=(2M)12(2L)_{2} ω$

Equating $L_{i}=L_{f}$

$⇒MVL/2=32 ML_{2}ω$

$⇒ω=43 LV $

The rod which has the velocity is sticking to the stationary rod which is at the top. After sticking the inertia of the stationary rod will make the whole rod to rotate in counterclockwise direction. Hence A and C is correct.

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