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A batsman hits back a ball straight in the direction of the bowier without changing its initial speed of 12ms. If the mass of the ball is 0.15 kg determine the impulse imparted to the ball. [Assume linear motion of the ball] Ans. Change in momentum = 0.15 X 12-(-0.15 x 12) = 3.6NS, Impulse = 3.6NS.

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