0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

# A battery of 9 V is connected in series with resistors of 0.2 Ω,0.3 Ω,0.4 Ω,0.5Ω and 12 Ω respectively. How much current will flow through the 12 Ω resistor?

Solution
Verified by Toppr

#### For resistors in series, Req=R1+R2+R3+R4+R5 =0.2+0.3+0.4+0.5+12 =13.4 Ω By ohm's Law:V=IReq9=13.4II=0.67 AWhen resistors are connected in series, current is same in all the resistors. Hence, current in 12 Ω resistor =0.67 A.

229
Similar Questions
Q1
A battery of 9 V is connected in series with resistors of 0.2 Ω,0.3 Ω,0.4 Ω,0.5Ω and 12 Ω respectively. How much current will flow through the 12 Ω resistor?
View Solution
Q2
Question 9
A battery of 9 V is connected in series with resistors of 0.2Ω,0.3Ω,0.4Ω,0.5Ω and 12Ω, respectively. How much current would flow through the 12Ω resistors?
View Solution
Q3

A battery of 9 V is connected in series with resistance of 0.2Ω, 0.3Ω, 5Ω, 0.5Ωand12Ω respectively. How much current would flow through the 12Ω resistor?

View Solution
Q4

A battery of 13 V is connected in series with resistors of 2 Ω,3 Ω,4 Ω,5 Ω and 12 Ω, respectively. How much current would flow through the 12 Ω resistors?

View Solution
Q5

A battery of 9V is connected in series with resistor of 0.2,0.3,0.4,0.5,12 Ohm. How much current would flow through the12 Ohm resistor?

View Solution