A battery of emf 10 V and internal resistance 3 W is connected to a resistor- If the current in the circuit is 0-5 A- what is the resistance of the resistor- What is the terminal voltage of the battery when the circuit is closed-

Question

Toppr Admin · Accepted Answer

E-V-IR-R-E-I-x2212-V-17-xA0-x3A9-Again using E-V-Ir- we getV-E-x2212-Ir-10-x2212-0-5-xD7-3-xA0- -xA0- -10-x2212-1-5-8-5V-

A battery of emf 10 V and internal resistance 3 W is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistance of the resistor? What is the terminal voltage of the battery when the circuit is closed?

$E = V + I R$ ,
$R = E / I - V = 17 Ω$

Again using $E = V + I r$ , we get
$V = E - I r = 10 - 0.5 \times 3$
$= 10 - 1.5 = 8.5 V$ .

A battery of emf 10 V and internal resistance 3 W is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistance of the resistor? What is the terminal voltage of the battery when the circuit is closed?

E=V+IR,R=E/I−V=17 ΩAgain using E=V+Ir, we getV=E−Ir=10−0.5×3 =10−1.5=8.5V.

$E = V + I R$ ,
$R = E / I - V = 17 Ω$

Again using $E = V + I r$ , we get
$V = E - I r = 10 - 0.5 \times 3$
$= 10 - 1.5 = 8.5 V$ .