A beam of parallel rays is incident on a transparent slab of refractive index √3 making an angle 30∘ with the surface of the slab. If the width of incident beam of light is 1.732 mm, the width of refracted beam is:
1.00 mm
2.50 mm
1.50mm
3.00 mm
A
1.50mm
B
2.50 mm
C
1.00 mm
D
3.00 mm
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Solution
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Using μ1sini=μ2sinr 1×sin60∘=√3sinr
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