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>> $A beam of parallel rays is incident on a$

Question

A beam of parallel rays is incident on a transparent slab of refractive index $3$ making an angle $3 0^{\circ}$ with the surface of the slab. If the width of incident beam of light is 1.732 mm, the width of refracted beam is:

A

1.00 mm

B

1.50mm

C

2.50 mm

D

3.00 mm

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Updated on : 2022-09-05

Solution

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Correct option is D)

Using $μ_{1} s i n i = μ_{2} s i n r$
$1 \times s i n 6 0^{\circ} = 3 s i n r$

$s i n r = \frac{1}{2}$

$A B = \frac{1 . 7 3 2 m m}{c o s i}$

Now,

$B B^{1} = A B c o s r$

$= \frac{1 . 7 3 2}{c o s i} \times c o s r$

$= \frac{1 . 7 3 2}{\frac{1}{2}} \times \frac{3}{2} = 3 m m$

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