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>>Ray Optics and Optical Instruments
>>Combination of Mirror and Lenses
>> $A biconvex lens of refractive index mu 1$

Question

A biconvex lens of refractive index $μ_{1}$ , is immersed in a liquid of refractive index $μ_{2}$ . If a beam of parallel rays incident on the lens and the emergent rays are divergent then the correct choice is

A

$μ_{1} > μ_{2}$

B

$μ_{1} < μ_{2}$

C

$μ_{1} = μ_{2}$

D

$μ_{2} = \frac{μ _{1}}{2}$

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Updated on : 2022-09-05

Solution

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Correct option is B)

$μ_{1} \to μ_{2}$

$\frac{1}{f} = (μ_{e o q} - 1) (\frac{1}{R _{1}} - \frac{1}{R _{2}})$

$d i v e r g e n t \Rightarrow \frac{μ _{1}}{μ _{2}} - 1 < 0 \Rightarrow μ_{1} < μ_{2}$

since $b i c o n v e x \Rightarrow (\frac{1}{R _{1}} - \frac{1}{R _{2}}) > 0$

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