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A block A of mass 4kg is placed on another block B of mass 5kg and the block B rests on a smooth horizontal table. If the minimum force that can be applied on A so that both the blocks move together is 12N,find the maximum force that can be applied on B for the blocks to move together.
- 25 N
- 30 N
- 48 N
- 27 N
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Solution
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In the first case, friction acts only between the 4kg block and the 5kg block.
As a result if 12N is the force required for both the blocks to move together,
In the second case, we consider both the blocks as a system and the force acting between them is an internal force.
Thus the ratio of the forces applied on a block to the mass of the block should be a constant.
124=F9
Hence, the maximum force F = 27 N
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