A block of mass $2.0 k g$ is pushed down an inclined plane of inclination $37^{o}$ with a force of $20 N$ acting parallel to the incline. It is found that the block moves on the incline with an acceleration of $10 m / s^{2}$ . If the block started from rest, find the work done (a) by the applied force in the first second
100J
105J
150J
200J

150J

200J

105J

100J

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Solution

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we have,

$s = u t + \frac{1}{2} a t^{2}$

$= 0 + \frac{1}{2} \times 10 \times 1^{2}$

$= 5 m$
work done = 20*5 =100J

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we have,s=ut+12at2=0+12×10×12=5mwork done = 20*5 =100J

we have,

$s = u t + \frac{1}{2} a t^{2}$

$= 0 + \frac{1}{2} \times 10 \times 1^{2}$

$= 5 m$
work done = 20*5 =100J