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# A block of mass 2kg is hanging over a smooth and light pulley through a light string. The other end of the string is pulled by a constant force F=40N. The kinetic energy of the particle increases 40 J in a given interval of time. Work done by tension is 100 J120 J80 J40 J

A
120 J
B
100 J
C
80 J
D
40 J
Solution
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#### ⇒a=10m/s240−20=2aLet ui=0v=at=10ts=12×10v2=5v2⇒12×2×(10t2)=40⇒100t2=40⇒WT=40×5v2=200v2=80JHence,option (C) is correct answer.

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