physics

Correct option is

Let the total distance be $2x$.

For first half distance :

Speed is $20m/s$

Thus time taken $t_{1}=20x $

For second half distance :

Speed is $30m/s$

Thus time taken $t_{2}=30x $

Average velocity $V_{avg}=t_{1}+t_{2}2x $

$⟹V_{avg}=20x +30x 2x =20+302×20×30 =24m/s$

Answer verified by Toppr

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