A body is moving along a straight line. Its distance Xt from a point on its path at a time t after passing that point is given by Xt=8t2−3t3, where Xt is in meter and t is in second. The correct statement(s) is/are:
Average speed during the interval t=0 s to t=4s is 20.21ms−1
The body starts from rest and at t=169s it reverses its direction of motion at xt=8.43m from the start
Average velocity during the interval t=0 s to t=4s is −16ms−1
It has an acceleration of −56ms−2 at t=4s
A
Average speed during the interval t=0 s to t=4s is 20.21ms−1
B
Average velocity during the interval t=0 s to t=4s is −16ms−1
C
The body starts from rest and at t=169s it reverses its direction of motion at xt=8.43m from the start
D
It has an acceleration of −56ms−2 at t=4s
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Solution
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⇒Xt=8t2−3t3⇒dXtdt=V=16t−9t2⇒d2Xtdt2=a=16−18t
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