A body moves a distance of 10 m along a straight line under the action of a force of 5 N. If the work done is 25 joule, the angle which the force makes with the direction of motion of the body is

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Toppr Admin · Accepted Answer

W-Fscos-x3B8-cos-x3B8-WFs-255-xD7-10-12-x3B8-60-x2218-

A body moves a distance of $10$ m along a straight line under the action of a force of $5$ newtons. If the work done is $25$ joules, the angle which the force makes with the direction of motion of body is
$0^{\circ}$
$30^{\circ}$
$60^{\circ}$
$90^{\circ}$

$W = F s cos θ, c o s θ = \frac{W}{F s} = \frac{25}{5 \times 10} = \frac{1}{2}, θ = 60^{\circ}$

A body moves a distance of 10 m along a straight line under the action of a force of 5 newtons. If the work done is 25 joules, the angle which the force makes with the direction of motion of body is 0∘30∘60∘90∘

W=Fscosθ,cosθ=WFs=255×10=12,θ=60∘

A body moves a distance of $10$ m along a straight line under the action of a force of $5$ newtons. If the work done is $25$ joules, the angle which the force makes with the direction of motion of body is
$0^{\circ}$
$30^{\circ}$
$60^{\circ}$
$90^{\circ}$

$W = F s cos θ, c o s θ = \frac{W}{F s} = \frac{25}{5 \times 10} = \frac{1}{2}, θ = 60^{\circ}$