A body moves a distance of 10 m long a straight line under the action of force of 5N. If the work done is 25 joules, the angle which the force makes with the direction of motion of the body is:

Question

Toppr Admin · Accepted Answer

According to the question-we know that-xA0- W-F-SW-F-Scos-x3B8-25-x2212-5-xD7-10cos-x3B8-cos-x3B8-2550cos-x3B8-12-x3B8-60-x2218-

A body moves a distance of 10 m long a straight line under the action of force of 5N. If the work done is 25 joules, the angle which the force makes with the direction of motion of the body is:
$30^{0}$
$90^{0}$
$60^{0}$
$0^{0}$

According to the question,
we know that $W = F . S$
$W = F . S cos θ$
$25 - 5 \times 10 cos θ$
$cos θ = \frac{25}{50}$
$cos θ = \frac{1}{2}$
$θ = 60^{\circ}$

A body moves a distance of 10 m long a straight line under the action of force of 5N. If the work done is 25 joules, the angle which the force makes with the direction of motion of the body is:30090060000

According to the question,we know that W=F.SW=F.Scosθ25−5×10cosθcosθ=2550cosθ=12θ=60∘

A body moves a distance of 10 m long a straight line under the action of force of 5N. If the work done is 25 joules, the angle which the force makes with the direction of motion of the body is:
$30^{0}$
$90^{0}$
$60^{0}$
$0^{0}$

According to the question,
we know that $W = F . S$
$W = F . S cos θ$
$25 - 5 \times 10 cos θ$
$cos θ = \frac{25}{50}$
$cos θ = \frac{1}{2}$
$θ = 60^{\circ}$