A body of mass 0-2 kg falls from a height of 10m to a height of 6m above the ground- Find the loss in potential energy taking place in the body- -g-10ms-2-

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Given - m-0-2kg-g-10ms-x2212-2-h1-10m-h2-6m-Loss in P-E- -mg-h1-x2212-h2-0-2-xD7-10-xD7-10-10-x2212-6-0-2-xD7-10-xD7-4-8J

A body of mass 0.2 kg falls from a height of 10m to a height of 6m above the ground. Find the loss in potential energy taking place in the body. [ $g = 10 m s^{- 2}$ ].

Given : $m = 0.2 k g, g = 10 m s^{- 2}, h_{1} = 10 m, h^{2} = 6 m$ .
Loss in P.E. $= m g (h_{1} - h_{2})$
$= 0.2 \times 10 \times 10 (10 - 6)$
$= 0.2 \times 10 \times 4 = 8 J$

A body of mass 0.2 kg falls from a height of 10m to a height of 6m above the ground. Find the loss in potential energy taking place in the body. [g=10ms−2].

Given : m=0.2kg,g=10ms−2,h1=10m,h2=6m.Loss in P.E. =mg(h1−h2)=0.2×10×10(10−6)=0.2×10×4=8J

A body of mass 0.2 kg falls from a height of 10m to a height of 6m above the ground. Find the loss in potential energy taking place in the body. [ $g = 10 m s^{- 2}$ ].

Given : $m = 0.2 k g, g = 10 m s^{- 2}, h_{1} = 10 m, h^{2} = 6 m$ .
Loss in P.E. $= m g (h_{1} - h_{2})$
$= 0.2 \times 10 \times 10 (10 - 6)$
$= 0.2 \times 10 \times 4 = 8 J$